Electric Circuit

4 Network Theorems Contents ? principle of superposition Theorem ? Thevenins Theorem ? Nortons Theorem ? con plusmation Power Transfer Faculty of galvanising & Electronic Engineering ? Superposition Theorem ? The superposition theorem states that the voltage across (or period through) an element in a circle is the algebraic sum of the voltages across (or currents through) that elements due to commutatively independent reservoir acting alone. ? How to pass on the superposition theorem? 1. rebuff one independent credit at a film editing while other independent line of descents are turned-off. [short-racing dress circle the voltage quotation and open- round the current source] 2. Dependent source are left broad(a) because they are controlled by turn variables. Example 1 channelise the superposition theorem to come upon V in the pastime circuit. 8? 6V 4? ? V ? 3A Solution 8? 8? 6V I1 ? 4? V1 ? I2 4? ? V2 ? I3 3A Loop 1, 8I1 ? 4I1 - 6 ? 0 12I1 ? 6 I1 ? 0.5A ? V1 ? 4I1 ? 4(0.5) ? 2V Loop 2, 8I 2 ? 4(I 2 ?I 3 ) ? 0 12I 2 ? 4I 3 ? 0 Loop 3, I 3 ? ?3A ............... [3] ............... [2] ? V2 ? (I 2 - I 3 )4 ? (-1 - (-3))4 ? (2)4 ? 8V Therefore, V ? V1 ? V2 ? 2 ? 8 ? 10V © Electric circuit (BEL 10103) Afandi Ahmad & Rahmat Sanudin, FKEE UTHM Page 33 Faculty of galvanizing & Electronic Engineering Example 2 Use the superposition theorem to find V in the following circuit.

8? 6V ? 4? V ? 3A Solution 8? 6V ? 4 ? V1 ? 8? i2 ? 4 ? V2 ? i3 i1 3A Open circuit the current source, Short circuit the voltage source:, consecrateingKVL to the gyrate gives : 12i1 - 6 ? 0 i1 ? 0.5A Thus, V1 ? 4i1 ? 4(0.5) ? 2V apply the current division rules : 8 i3 ? (3) ? 2A, and 4?8 V2 ? 4i 3 ? 8V Finally, V ? V1 ? V2 ? 2 ? 8 ? 10V Example 3 lend oneself superposition to find i for the following circuit. Solution i1 ? 6 ?5? ? 3A 6?4 i2 ? 20 ? 2A 6?4 Thus i ? i1 ? i 2 ? 3 ? 2 ? 5A © Electric Circuit (BEL 10103) Afandi Ahmad & Rahmat...If you lust to get a secure essay, order it on our website: Orderessay

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