Physics

The slope for the up escalator averaged out to be .5 m/s since it took more or less 20 seconds to permit up the 10 meters that we make The slope of the down (-) escalator averaged out to be -.4 m/s + 10 because it took the object 25 seconds to go 10 meters. For our data, we individually measured a stair which figure out out to be .3 meters and we marked on the stairs so we could count each one that went by until we saw the sign again, and we found that there were 30 stairs. So .3 meters x 30 stairs = 10 meters = Total outperform of stair case. then(prenominal) we fixed an object, a person, on the up escalator, and tested how gigantic it would leave the person to get the precede of the stair case, the sum distance being 10 meters. Since we looked at exhalation to the top as positive, the initial position was secret code because it started at zip fastener meters and was working their way to the top to 10 meters. After 8 trials, we averaged our numbers out and g ot 20.00434 seconds, which is approximately 20 seconds. Then we did a variety and set up 10m/20s = x(m)/1s and got .5.

So the equation for this would be position (x) (m) = (.5m/s)(t) We did the resembling thing for the down escalator and got the same coat of ten meters. Since we were going down we look at it as a forbid direction and our intitial position would be 10 meters. After 8 trials, we averaged out to be 25.0065 seconds, so approximately 25 seconds. Similar to the first one, we did a conversion and got .4 m/s as the speed and since it was a negative velocity, it was going -.4 m/s. The equation for the down escaslator would be position(x)= (.4m/s)(t) + 10mIf you call for to get a full essay, order it on our website: OrderEssay.net

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